Optimal. Leaf size=295 \[ -\frac{i b^2 \sqrt{1-c^2 x^2} \text{PolyLog}\left (2,-e^{2 i \sin ^{-1}(c x)}\right )}{c^3 d e \sqrt{c d x+d} \sqrt{e-c e x}}-\frac{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^3}{3 b c^3 d e \sqrt{c d x+d} \sqrt{e-c e x}}-\frac{i \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^2}{c^3 d e \sqrt{c d x+d} \sqrt{e-c e x}}+\frac{2 b \sqrt{1-c^2 x^2} \log \left (1+e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{c^3 d e \sqrt{c d x+d} \sqrt{e-c e x}}+\frac{x \left (a+b \sin ^{-1}(c x)\right )^2}{c^2 d e \sqrt{c d x+d} \sqrt{e-c e x}} \]
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Rubi [A] time = 0.74251, antiderivative size = 295, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.229, Rules used = {4739, 4703, 4641, 4675, 3719, 2190, 2279, 2391} \[ -\frac{i b^2 \sqrt{1-c^2 x^2} \text{PolyLog}\left (2,-e^{2 i \sin ^{-1}(c x)}\right )}{c^3 d e \sqrt{c d x+d} \sqrt{e-c e x}}-\frac{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^3}{3 b c^3 d e \sqrt{c d x+d} \sqrt{e-c e x}}-\frac{i \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^2}{c^3 d e \sqrt{c d x+d} \sqrt{e-c e x}}+\frac{2 b \sqrt{1-c^2 x^2} \log \left (1+e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{c^3 d e \sqrt{c d x+d} \sqrt{e-c e x}}+\frac{x \left (a+b \sin ^{-1}(c x)\right )^2}{c^2 d e \sqrt{c d x+d} \sqrt{e-c e x}} \]
Antiderivative was successfully verified.
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Rule 4739
Rule 4703
Rule 4641
Rule 4675
Rule 3719
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{x^2 \left (a+b \sin ^{-1}(c x)\right )^2}{(d+c d x)^{3/2} (e-c e x)^{3/2}} \, dx &=\frac{\sqrt{1-c^2 x^2} \int \frac{x^2 \left (a+b \sin ^{-1}(c x)\right )^2}{\left (1-c^2 x^2\right )^{3/2}} \, dx}{d e \sqrt{d+c d x} \sqrt{e-c e x}}\\ &=\frac{x \left (a+b \sin ^{-1}(c x)\right )^2}{c^2 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\sqrt{1-c^2 x^2} \int \frac{\left (a+b \sin ^{-1}(c x)\right )^2}{\sqrt{1-c^2 x^2}} \, dx}{c^2 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\left (2 b \sqrt{1-c^2 x^2}\right ) \int \frac{x \left (a+b \sin ^{-1}(c x)\right )}{1-c^2 x^2} \, dx}{c d e \sqrt{d+c d x} \sqrt{e-c e x}}\\ &=\frac{x \left (a+b \sin ^{-1}(c x)\right )^2}{c^2 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^3}{3 b c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\left (2 b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int (a+b x) \tan (x) \, dx,x,\sin ^{-1}(c x)\right )}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}\\ &=\frac{x \left (a+b \sin ^{-1}(c x)\right )^2}{c^2 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{i \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^2}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^3}{3 b c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}+\frac{\left (4 i b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{e^{2 i x} (a+b x)}{1+e^{2 i x}} \, dx,x,\sin ^{-1}(c x)\right )}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}\\ &=\frac{x \left (a+b \sin ^{-1}(c x)\right )^2}{c^2 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{i \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^2}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^3}{3 b c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}+\frac{2 b \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+e^{2 i \sin ^{-1}(c x)}\right )}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\left (2 b^2 \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \log \left (1+e^{2 i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}\\ &=\frac{x \left (a+b \sin ^{-1}(c x)\right )^2}{c^2 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{i \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^2}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^3}{3 b c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}+\frac{2 b \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+e^{2 i \sin ^{-1}(c x)}\right )}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}+\frac{\left (i b^2 \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{2 i \sin ^{-1}(c x)}\right )}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}\\ &=\frac{x \left (a+b \sin ^{-1}(c x)\right )^2}{c^2 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{i \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^2}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^3}{3 b c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}+\frac{2 b \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+e^{2 i \sin ^{-1}(c x)}\right )}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}-\frac{i b^2 \sqrt{1-c^2 x^2} \text{Li}_2\left (-e^{2 i \sin ^{-1}(c x)}\right )}{c^3 d e \sqrt{d+c d x} \sqrt{e-c e x}}\\ \end{align*}
Mathematica [B] time = 2.53003, size = 636, normalized size = 2.16 \[ \frac{b^2 \sqrt{d} e \left (-6 i \sqrt{1-c^2 x^2} \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(c x)}\right )-6 i \sqrt{1-c^2 x^2} \text{PolyLog}\left (2,i e^{i \sin ^{-1}(c x)}\right )-\sqrt{1-c^2 x^2} \sin ^{-1}(c x)^3-3 i \sqrt{1-c^2 x^2} \sin ^{-1}(c x)^2+6 i \pi \sqrt{1-c^2 x^2} \sin ^{-1}(c x)+6 \sqrt{1-c^2 x^2} \sin ^{-1}(c x) \log \left (1-i e^{i \sin ^{-1}(c x)}\right )+6 \sqrt{1-c^2 x^2} \sin ^{-1}(c x) \log \left (1+i e^{i \sin ^{-1}(c x)}\right )+12 \pi \sqrt{1-c^2 x^2} \log \left (1+e^{-i \sin ^{-1}(c x)}\right )+3 \pi \sqrt{1-c^2 x^2} \log \left (1-i e^{i \sin ^{-1}(c x)}\right )-3 \pi \sqrt{1-c^2 x^2} \log \left (1+i e^{i \sin ^{-1}(c x)}\right )-3 \pi \sqrt{1-c^2 x^2} \log \left (\sin \left (\frac{1}{4} \left (2 \sin ^{-1}(c x)+\pi \right )\right )\right )-12 \pi \sqrt{1-c^2 x^2} \log \left (\cos \left (\frac{1}{2} \sin ^{-1}(c x)\right )\right )+3 \pi \sqrt{1-c^2 x^2} \log \left (-\cos \left (\frac{1}{4} \left (2 \sin ^{-1}(c x)+\pi \right )\right )\right )+3 c x \sin ^{-1}(c x)^2\right )+3 a^2 \sqrt{e} \sqrt{c d x+d} \sqrt{e-c e x} \tan ^{-1}\left (\frac{c x \sqrt{c d x+d} \sqrt{e-c e x}}{\sqrt{d} \sqrt{e} \left (c^2 x^2-1\right )}\right )+3 a^2 c \sqrt{d} e x+3 a b \sqrt{d} e \left (\sqrt{1-c^2 x^2} \left (2 \left (\log \left (\cos \left (\frac{1}{2} \sin ^{-1}(c x)\right )-\sin \left (\frac{1}{2} \sin ^{-1}(c x)\right )\right )+\log \left (\sin \left (\frac{1}{2} \sin ^{-1}(c x)\right )+\cos \left (\frac{1}{2} \sin ^{-1}(c x)\right )\right )\right )-\sin ^{-1}(c x)^2\right )+2 c x \sin ^{-1}(c x)\right )}{3 c^3 d^{3/2} e^2 \sqrt{c d x+d} \sqrt{e-c e x}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.338, size = 0, normalized size = 0. \begin{align*} \int{{x}^{2} \left ( a+b\arcsin \left ( cx \right ) \right ) ^{2} \left ( cdx+d \right ) ^{-{\frac{3}{2}}} \left ( -cex+e \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b^{2} x^{2} \arcsin \left (c x\right )^{2} + 2 \, a b x^{2} \arcsin \left (c x\right ) + a^{2} x^{2}\right )} \sqrt{c d x + d} \sqrt{-c e x + e}}{c^{4} d^{2} e^{2} x^{4} - 2 \, c^{2} d^{2} e^{2} x^{2} + d^{2} e^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \arcsin \left (c x\right ) + a\right )}^{2} x^{2}}{{\left (c d x + d\right )}^{\frac{3}{2}}{\left (-c e x + e\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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